Probability Statistics SAT / ACT / GRE / GMAT 25 min read May 30, 2026
BY: Statistics Fundamentals Team
Reviewed By: Minsa A (Senior Statistics Editor)

Probability Rules: Complete Guide to the Laws of Probability

Six rules govern every probability calculation ever made. Know them, and you can solve any probability problem — exam questions, real-world scenarios, data science applications — from first principles. This reference covers every core rule with its formula, the exact condition that activates it, plain-English meaning, and a fully worked example.

The most common exam mistake — and the single thing this guide fixes — is applying the wrong rule. Add when you should multiply, forget to subtract the overlap, or use the independent formula on dependent events, and the answer is wrong even though the arithmetic is right. This guide teaches you which rule to reach for, and why.

What You'll Learn
  • ✓ All 6 core probability rules — formula, condition, and plain-English meaning
  • ✓ The Ultimate Probability Rules Master Matrix (cheat sheet table)
  • ✓ Interactive "Add or Multiply?" decision tree — find the right rule instantly
  • ✓ 4 fully worked examples: dice, card draws, coin + die, consecutive draws
  • ✓ Venn diagram and tree diagram visual guides
  • ✓ The #1 exam pitfall and how to avoid it
  • ✓ An interactive calculator for all four rules

What Are the Rules of Probability?

Definition — Probability Rules
The rules of probability are a set of mathematical laws that define how probabilities behave, combine, and constrain each other. They establish the boundaries every probability must obey, and the exact formulas for computing the likelihood of compound events — events that combine two or more outcomes using the words "OR" or "AND."
0 ≤ P(A) ≤ 1  |  P(A) + P(A') = 1

Every probability you will ever compute — whether for a coin flip, a card game, a machine failure rate, or a clinical trial — is governed by the same six rules. They are not arbitrary conventions. They follow logically from a single axiom: the set of all possible outcomes (the sample space) must have total probability exactly equal to 1.

According to the foundational axioms of probability theory first formalized by the Soviet mathematician Andrei Kolmogorov in 1933, and as presented in standard statistics textbooks such as OpenStax Introductory Statistics (available free at openstax.org), the entire structure of modern probability rests on three axioms: non-negativity, unit measure (total probability = 1), and countable additivity. The six rules covered here are direct consequences.

6
Core Rules
0 → 1
Probability Range
OR = +
Key Anchor: Addition
AND = ×
Key Anchor: Multiplication
Academic Source: Kolmogorov, A. N. (1933). Foundations of the Theory of Probability. Chelsea Publishing (English translation, 1950). The probability axioms presented here derive directly from this foundational work, and are consistent with treatment in the MIT OpenCourseWare probability curriculum (MIT OCW 6.041).

The 6 Core Probability Rules

The following six rules cover every fundamental operation in probability. Each one has a specific activation condition — the situation that determines whether it applies. Learn the conditions, and you will always know which rule to use.

Rule 1: The Range Rule (Probability Boundaries)

Rule 1 — Range Rule
0 ≤ P(A) ≤ 1
Read: "The probability of any event A is always between 0 and 1, inclusive."
Condition: Always — applies to every probability
P(A) = 0 → Impossible event
P(A) = 1 → Certain event
P(A) = 0.5 → Even chance (50/50)

The Range Rule is the gatekeeper of all probability. It says that every probability must be a number between 0 and 1, inclusive. A probability of 0 means the event is impossible — it will never happen under any circumstance within the defined experiment. A probability of 1 means the event is certain — it will happen every single time. Any probability in between represents a partial likelihood.

🚨
Critical Check: Result Outside 0–1?

If your calculated probability is negative or greater than 1, you have made an error. The most common cause is forgetting to subtract P(A ∩ B) in the General Addition Rule for overlapping events, causing the result to exceed 1. Go back and recheck your inputs and formula choice.

Rule 2: The Complement Rule

Rule 2 — Complement Rule
P(A') = 1 − P(A)
Read: "The probability of A NOT occurring equals one minus the probability of A occurring."
Condition: Always — use when the complement is easier to compute
A' = "not A" = complement of A
P(A) + P(A') = 1 always

The Complement Rule is one of the most useful shortcuts in probability. Since every outcome in the sample space either belongs to event A or does not belong to event A — with no overlap and nothing left out — the probabilities P(A) and P(A') must sum to exactly 1. Therefore, if you know one, you know the other.

The complement is especially powerful when computing "at least one" problems. Instead of listing every way at least one success can occur, you compute 1 minus the probability of zero successes, which is usually a single calculation.

Worked Example — Complement Rule

Problem: A bag contains 3 red and 7 blue marbles. What is the probability of NOT drawing red?

1

Find P(red). There are 3 red marbles out of 10 total: P(red) = 3/10 = 0.3

2

Apply the Complement Rule. P(not red) = 1 − P(red) = 1 − 0.3 = 0.7

✓ P(not red) = 0.7 (70%). This matches the direct count: 7 blue marbles / 10 total = 7/10 = 0.7 ✓

Rule 3: The Addition Rule (Mutually Exclusive Events)

Rule 3 — Addition Rule (Mutually Exclusive / Disjoint)
P(A ∪ B) = P(A) + P(B)
Read: "The probability of A OR B equals P(A) plus P(B) — but only when A and B cannot both occur."
Condition: Events A and B are MUTUALLY EXCLUSIVE (P(A ∩ B) = 0)
= union = "OR"
= intersection = "AND"
Mutually exclusive = cannot both happen

Two events are mutually exclusive (also called disjoint) when they share no outcomes — they cannot occur simultaneously in a single trial. On a single roll of a die, rolling a 3 and rolling a 5 are mutually exclusive: you cannot get both on one roll. For such events, the addition rule is simple: just add the probabilities directly.

Worked Example 1 — Addition Rule (Mutually Exclusive)

Problem: What is the probability of rolling a 3 OR a 5 on a single fair six-sided die?

1

Identify the events. A = roll a 3, B = roll a 5. Both have 1 favorable outcome out of 6 total. P(A) = 1/6, P(B) = 1/6.

2

Check for mutual exclusivity. On one roll, can you get both 3 AND 5? No — a single die shows exactly one face. Therefore A and B are mutually exclusive: P(A ∩ B) = 0.

3

Apply Rule 3. P(3 or 5) = P(3) + P(5) = 1/6 + 1/6 = 2/6 = 1/3

✓ P(rolling a 3 or a 5) = 2/6 = 1/3 ≈ 0.333 (33.3%). Direct verification: {3, 5} are 2 favorable outcomes out of 6 total = 2/6 ✓

Rule 4: The General Addition Rule (Overlapping Events)

Rule 4 — General Addition Rule (Overlapping / Non-Mutually Exclusive)
P(A ∪ B) = P(A) + P(B) − P(A ∩ B)
Read: "The probability of A OR B equals P(A) plus P(B) minus the probability of both A and B occurring."
Condition: Events A and B CAN OVERLAP — P(A ∩ B) > 0
P(A ∩ B) = intersection = both A AND B occur
Subtract to avoid double-counting the overlap

When events can co-occur — when the outcome of one event is compatible with the outcome of another — simply adding P(A) + P(B) counts their shared outcomes twice. The General Addition Rule corrects this by subtracting P(A ∩ B), the probability of both events happening at the same time. This is the formula to use any time the word "OR" connects two events that are not mutually exclusive.

⚠️
The #1 Student Mistake — Forgetting to Subtract the Intersection

Using P(A ∪ B) = P(A) + P(B) when the events overlap is the single most common error on probability exams. Always ask: "Can both events occur at the same time?" If the answer is yes, you must subtract P(A ∩ B). Skipping this step overcounts the shared outcomes and gives an answer greater than the true probability — sometimes even exceeding 1.

Worked Example 2 — General Addition Rule (Overlapping)

Problem: What is the probability of drawing a King OR a Red card from a standard 52-card deck?

1

Identify the events and their counts. A = King: 4 Kings in 52 cards. B = Red card: 26 red cards (13 hearts + 13 diamonds) in 52 cards.

2

Find the intersection. A ∩ B = King AND Red = Red Kings. There are exactly 2 Red Kings (King of Hearts, King of Diamonds). P(A ∩ B) = 2/52.

3

Apply Rule 4. P(King or Red) = P(King) + P(Red) − P(King and Red) = 4/52 + 26/52 − 2/52 = 28/52 = 7/13

✓ P(King or Red card) = 28/52 = 7/13 ≈ 0.538 (53.8%). Direct count: 26 red cards + 2 black kings (non-red kings) = 28 favorable cards ✓

Rule 5: The Multiplication Rule (Independent Events)

Rule 5 — Multiplication Rule (Independent Events)
P(A ∩ B) = P(A) × P(B)
Read: "The probability of A AND B both occurring equals P(A) multiplied by P(B) — but only when A and B are independent."
Condition: Events A and B are INDEPENDENT — P(B|A) = P(B)
= intersection = "AND"
Independent = A's outcome does not change P(B)
e.g., flipping a coin, then rolling a die

Two events are independent when knowing the outcome of one provides no information about the other. Flipping a coin and rolling a die are independent: heads or tails on the coin has no bearing on what number appears on the die. For independent events, multiply the individual probabilities.

Worked Example 3 — Multiplication Rule (Independent)

Problem: What is the probability of flipping Heads AND rolling a 6 simultaneously?

1

Identify independence. The coin flip and the die roll are separate experiments. One cannot influence the other — they are independent events.

2

Find individual probabilities. P(Heads) = 1/2. P(rolling a 6) = 1/6.

3

Apply Rule 5. P(Heads AND 6) = P(Heads) × P(6) = 1/2 × 1/6 = 1/12

✓ P(Heads and rolling 6) = 1/12 ≈ 0.0833 (8.33%). The sample space has 12 equally likely outcomes (2 coin × 6 die), and only 1 is (H, 6) ✓

Rule 6: The Multiplication Rule (Dependent Events)

Rule 6 — Multiplication Rule (Dependent Events)
P(A ∩ B) = P(A) × P(B|A)
Read: "The probability of A AND B both occurring equals P(A) multiplied by the probability of B GIVEN that A has occurred."
Condition: Events A and B are DEPENDENT — P(B|A) ≠ P(B)
P(B|A) = conditional probability of B given A
Dependent = first outcome changes the second probability
e.g., drawing cards without replacement

Events are dependent when the outcome of the first changes the probability of the second. The classic example is drawing cards without replacement: once the first card is removed from the deck, the total count drops from 52 to 51, and the probability of any specific card on the second draw changes accordingly. The notation P(B|A) — the conditional probability of B given A — captures this updated probability.

🚨
Do Not Use the Independent Rule on Dependent Events

Using P(A ∩ B) = P(A) × P(B) when drawing cards without replacement (or any "without replacement" scenario) is incorrect. After the first draw, the deck has 51 cards, not 52. Always update the probability for the second event based on what the first event removed.

Worked Example 4 — Multiplication Rule (Dependent)

Problem: Drawing two Aces consecutively from a standard deck without replacement.

1

First draw. There are 4 Aces in a 52-card deck. P(Ace on 1st draw) = 4/52 = 1/13.

2

Update for the second draw. Since no replacement occurs, the deck now has 51 cards and only 3 remaining Aces. The conditional probability P(Ace on 2nd | Ace on 1st) = 3/51 = 1/17.

3

Apply Rule 6. P(Ace, then Ace) = P(1st Ace) × P(2nd Ace | 1st Ace) = 4/52 × 3/51 = 12/2652 = 1/221

✓ P(two consecutive Aces, no replacement) = 1/221 ≈ 0.00452 (0.452%). Compare the wrong answer using the independent rule: 4/52 × 4/52 = 16/2704 ≈ 0.59% — that overcounts by ~30% and is incorrect.

The Ultimate Probability Rules Master Matrix

This table is your complete reference for all six probability rules. Every rule in one place: name, formula, required condition, and plain-English meaning. Bookmark it, print it, and paste it into your notes.

Rule Name Formula Condition Required Plain English Meaning
Range Rule 0 ≤ P(A) ≤ 1 Always Every probability must be between 0 (impossible) and 1 (certain). Any answer outside this range is wrong.
Complement Rule P(A') = 1 − P(A) Always The probability that event A does NOT happen equals one minus the probability that it does. P(A) + P(A') = 1 always.
Addition Rule (Mutually Exclusive) P(A ∪ B) = P(A) + P(B) Mutually Exclusive P(A ∩ B) = 0 For OR events that cannot both happen: just add. Rolling a 3 OR a 5 on one die — they cannot both land simultaneously.
General Addition Rule (Overlapping) P(A ∪ B) = P(A) + P(B) − P(A ∩ B) Overlapping P(A ∩ B) > 0 For OR events that can both happen: add, then subtract the overlap to avoid counting it twice. Drawing a King OR a Red card.
Multiplication Rule (Independent) P(A ∩ B) = P(A) × P(B) Independent P(B|A) = P(B) For AND events that don't affect each other: multiply. Flipping heads AND rolling a 6 — the coin tells you nothing about the die.
Multiplication Rule (Dependent) P(A ∩ B) = P(A) × P(B|A) Dependent P(B|A) ≠ P(B) For AND events where the first changes the second: multiply P(A) by the updated probability of B. Drawing two Aces without replacement.
The Two Golden Anchors

OR always triggers an Addition Rule (+). AND always triggers a Multiplication Rule (×). The next question is always: what kind of OR or AND? That determines which specific version of the rule to use.

The "Add or Multiply?" Decision Tree

Use this decision tree whenever you face a probability problem and are unsure which rule to apply. Start at the top, answer each question, and follow the branch to the exact rule you need.

🔀 Which Probability Rule Do I Use?

Step 1: Does the problem use the word "OR" or "AND"?
🟢 "OR" → Addition Rules

Can A and B happen at the same time?

NO → Mutually Exclusive
Use Addition Rule 3
P(A ∪ B) = P(A) + P(B)
YES → Overlapping Events
Use General Addition Rule 4
P(A ∪ B) = P(A) + P(B) − P(A ∩ B)
🔵 "AND" → Multiplication Rules

Does the first event affect the probability of the second?

NO → Independent Events
Use Multiplication Rule 5
P(A ∩ B) = P(A) × P(B)
YES → Dependent Events
Use Multiplication Rule 6
P(A ∩ B) = P(A) × P(B|A)

💡 Tip: "Without replacement" problems are almost always dependent. "With replacement" problems are almost always independent.

Visual Explanations: Venn Diagrams and Tree Diagrams

Venn Diagrams: Visualizing Addition Rules

Venn diagrams use overlapping circles to represent events within a sample space (the surrounding rectangle, labeled S). The area of a region corresponds to its probability. They are the clearest way to visualize the difference between mutually exclusive and overlapping events.

📊 Figure 1 — Venn Diagram: Mutually Exclusive vs. Overlapping Events
MUTUALLY EXCLUSIVE A B P(A ∩ B) = 0 → Use P(A) + P(B)

No overlap — circles are separate.
Rule 3 applies: P(A ∪ B) = P(A) + P(B)

OVERLAPPING A B A∩B Subtract intersection → Use P(A)+P(B)−P(A∩B)

Overlap exists — subtract intersection.
Rule 4 applies: P(A ∪ B) = P(A) + P(B) − P(A ∩ B)

Tree Diagrams: Visualizing Multiplication Rules

A tree diagram maps every possible sequence of outcomes as branches of a tree. Each branch is labeled with its probability. To find the probability of a complete path (a sequence of outcomes), multiply the probabilities along that path. Tree diagrams make the Multiplication Rule visual and intuitive.

📊 Figure 2 — Tree Diagram: Flipping a Coin Then Rolling a Die (Independent Events) Start 1/2 1/2 H T 1/6 1/6 1/6 1/6 (H,1) (H,2) (H,6)★ (T,1) (T,2) P = 1/2 × 1/6 = 1/12 12 total equally likely paths (2 × 6 = 12)

Each path = multiply probabilities along that branch. P(H, 6) = 1/2 × 1/6 = 1/12 (starred path above). This is the Multiplication Rule for Independent Events in visual form.

Probability Rules Calculator

Use the interactive calculator below to apply any of the four operational probability rules to your own numbers. Select the rule tab, enter your values, and click Calculate.

Probability Rules Calculator

Enter P(A) to find P(A') = 1 − P(A)

General Addition Rule: P(A ∪ B) = P(A) + P(B) − P(A ∩ B). For mutually exclusive events, enter 0 for P(A ∩ B).

For independent events: P(A ∩ B) = P(A) × P(B). For dependent events: enter P(B|A) in the second field.

Critical Pitfalls: The Most Common Probability Mistakes

These are the errors that cost students marks on exams. Each one stems from applying a rule without checking its required condition first.

Mistake Wrong Approach Correct Approach Rule Violated
Forgetting to subtract the intersection P(King or Red) = 4/52 + 26/52 = 30/52 P(King or Red) = 4/52 + 26/52 − 2/52 = 28/52 Rule 4 (General Addition)
Using independent multiplication on dependent draws P(Ace, Ace) = 4/52 × 4/52 = 16/2704 P(Ace, Ace) = 4/52 × 3/51 = 12/2652 Rule 6 (Dependent Multiplication)
Probability exceeding 1 P(A ∪ B) = 0.7 + 0.6 = 1.3 ✗ P(A ∪ B) = 0.7 + 0.6 − P(A ∩ B) ≤ 1 Rule 1 (Range Rule)
Treating overlapping events as mutually exclusive P(even or ≥4 on die) = 3/6 + 3/6 = 1.0 P(even or ≥4) = 3/6 + 3/6 − 2/6 = 4/6 (overlap: {4, 6}) Rule 4 vs Rule 3
Confusing complement with subtraction P(not getting 2 Aces) = 1 − P(1 Ace) P(not getting 2 Aces) = 1 − P(getting 2 Aces exactly) Rule 2 (Complement)
⚠️
The "Total Probability Cannot Exceed 1" Check

After every calculation, verify your answer is between 0 and 1. If P(A ∪ B) comes out greater than 1, you almost certainly forgot to subtract P(A ∩ B). If it is negative, check that P(A ∩ B) is not larger than either P(A) or P(B) — the intersection can never exceed either individual event's probability.

Key Vocabulary: Probability Rules Glossary

These are the precise definitions every probability rule depends on. Understanding these terms is prerequisite to applying the rules correctly.

Term Notation Definition
Sample SpaceS or ΩThe complete set of all possible outcomes of an experiment. Total probability across all outcomes = 1.
EventA, B, CAny subset of the sample space — one or more outcomes of interest.
ComplementA' or AᶜAll outcomes in the sample space that are NOT in event A. P(A) + P(A') = 1.
UnionA ∪ B"A OR B" — all outcomes that belong to A, B, or both.
IntersectionA ∩ B"A AND B" — outcomes that belong to both A and B simultaneously.
Mutually ExclusiveP(A ∩ B) = 0Events that cannot both occur. Their circles on a Venn diagram do not overlap.
Independent EventsP(B|A) = P(B)Events where knowing A occurred gives no information about whether B will occur.
Dependent EventsP(B|A) ≠ P(B)Events where A's outcome changes the probability of B. Common in "without replacement" problems.
Conditional ProbabilityP(B|A)The probability of B occurring given that A has already occurred. Formula: P(A ∩ B) / P(A).
Joint ProbabilityP(A ∩ B)The probability that both A and B occur together. Calculated using multiplication rules.

Probability Rules Quick Reference Cheat Sheet

This is a condensed cheat sheet for all six rules. Print this section or bookmark this page for fast reference during homework, exams, or study sessions. The formulas below match standard textbook notation as used by Khan Academy, OpenStax, and Wolfram MathWorld.

Rule 1

Range Rule

0 ≤ P(A) ≤ 1

All probabilities fall between 0 and 1 inclusive. P = 0 is impossible; P = 1 is certain.

Applies: Always
Rule 2

Complement Rule

P(A') = 1 − P(A)

Probability of "not A" = 1 minus probability of A. P(A) + P(A') = 1 always.

Applies: Always
Rule 3

Addition (Mutually Exclusive)

P(A ∪ B) = P(A) + P(B)

OR of events that cannot both happen. P(A ∩ B) = 0.

Condition: Mutually Exclusive
Rule 4

General Addition (Overlapping)

P(A ∪ B) = P(A)+P(B)−P(A∩B)

OR of events that can both happen. Subtract overlap to avoid double-counting.

Condition: Overlapping Events
Rule 5

Multiplication (Independent)

P(A ∩ B) = P(A) × P(B)

AND of events where one does not affect the other. Multiply directly.

Condition: Independent
Rule 6

Multiplication (Dependent)

P(A ∩ B) = P(A) × P(B|A)

AND of events where first changes the second. Use conditional probability P(B|A).

Condition: Dependent
⚡ Exam Cheat Sheet — Probability Rules at a Glance
  • Range: 0 ≤ P(A) ≤ 1 — never below 0, never above 1
  • Complement: P(A') = 1 − P(A) — probability of "not A"
  • OR + Mutually Exclusive: P(A ∪ B) = P(A) + P(B)
  • OR + Overlapping: P(A ∪ B) = P(A) + P(B) − P(A ∩ B)
  • AND + Independent: P(A ∩ B) = P(A) × P(B)
  • AND + Dependent: P(A ∩ B) = P(A) × P(B|A)
  • Memory anchor: OR = Add  |  AND = Multiply
  • Conditional probability: P(B|A) = P(A ∩ B) / P(A)

Build On These Rules: Next Topics to Study

Mastering the six probability rules opens the door to more advanced topics. The rules covered here are prerequisites for everything below.

Next Steps in Probability

Where These Rules Lead

Builds on Rules 3–6

Deepens your understanding of P(B|A) and dependent events. Required for Bayes' Theorem.

Builds on Rule 6

Uses the dependent multiplication rule to update probabilities in light of new evidence.

Applies all rules

The foundational page that establishes P(A) = favorable/total before the rules are applied.

For additional worked problems aligned to standardized exam format, the Khan Academy Probability Library offers free, structured practice. For rigorous mathematical definitions, Wolfram MathWorld's Probability section provides formal notation consistent with academic coursework. The OpenStax Introductory Statistics textbook Chapter 3 covers these rules in a peer-reviewed, freely available format cited by university courses worldwide.

Further Reading: The formal treatment of independence, conditional probability, and the multiplication theorem appears in DeGroot, M. H. & Schervish, M. J. (2012). Probability and Statistics, 4th ed. Addison-Wesley. This is a standard reference used in undergraduate statistics courses at institutions including MIT and Stanford.